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  1. #include <iostream>
  2. using namespace std;
  3. long long t[1000];
  4.  
  5. int main() {
  6.  
  7. 	int n;
  8. 	cin >> n;
  9. 	t[1]=1;
  10. 	t[2]=1;
  11.  
  12. 	for(int i=3; i<=n; i++)
  13. 	{
  14. 		t[i]=t[i-1]+t[i-2];
  15. 	}
  16.  
  17. 	cout << t[n] << endl;
  18.  
  19.  
  20. 	return 0;
  21. }
Success #stdin #stdout 0.01s 5320KB
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stdin
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stdout
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3736710778780434371
https://ideone.com/4BfqHm
777
language:
C++ (gcc 8.3)
created:
11 hours ago
visibility:
public

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